A major Blu-ray rental chain is considering opening a new store in an area that currently does not have any such stores. The chain will open if there is evidence that move than 5,000 of the 20,000 households in the area are equipped with Blu-ray players. It conducts a telephone poll of 300 randomly selected households in the area and finds that 96 have Blu-ray players. The value of the test statistic in this problem is approximately equal to 2.80. 2.60. 1.30. 1.94. A major Blu-ray rental chain considering opening a new store in an area that currently does not have any such stores. The chain will open if there is evidence that more than 5,000 of the 20,000 households in the area are equipped with Blu-ray players. It conducts a telephone poll of 300 randomly selected households in the area and finds beat 96 haw Blu-ray players. The p - value associated with the test statistic in this problem is approximately equal to 0.0100 0.0013. 00.0051. 0.0026. A major Blu-ray rental chain is considering opening a new store in an area that currently does not have any such stores. The chain will open if there is evidence that more than 5,000 of the 20.000 households in the area are equipped with Blu-ray players. It conducts a telephone poll of 300 randomly selected households in the area and finds beat 96 have Blu-ray players. The rental chain's conclusion from the hypothesis test using a 5% level of significance is to delay opening a new store until additional evidence is collected. not to open a new store. to open a new store. We cannot tell what bee derision should be from the information given. Microsoft Excel was used on a set of data involving the number of defective items found in a random sample of 46 cases of light bulbs produced during a morning shift at a plant A manager wants to know if the mean number of defective bulbs per case is greater than 20 during the morning shift She will make her decision using a test with a level of significance of 0.10. The following information was extracted from the Microsoft Excel output for the sample of 46 saws: n = 46, Arithmetic Mean = 28.00; Standard Deviation = 25.92; Standard Error = 3.82; Null Hypothesis; H_0; mu lessthanorequalto 20; a = 0.10; df = 45; T Test Statistic = 2.09; One-Tail Test Upper Critical Value = 1.3006; p-value = 0.021; Decision = Reject.